解释此代码段? [英] Explain this code snippet?

问题描述

任何人都可以解释该程序如何工作

Can anyone explain how the program works

#include<stdio.h>
#include<math.h>
int main()
{
    float a=5.375;
    char *p;
    int i;
    p = (char*)&a;
    for(i=0; i<=3; i++)
        printf("%02x\n", (unsigned char)p[i]);
    return 0;
}

问候

推荐答案

float有四个字节，而char是一个字节(通常在32位系统上)，程序只是加载(第一个字节)指向字符指针p，然后遍历字节并以十六进制打印值.

float has four bytes and char is one byte (usually, on 32 bit systems), the program is simply loading the address of a (the first byte) to character pointer p, then running though the bytes and printing the value in hex.

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