java使用数字浮点数 [英] java using number float

问题描述

我有两个浮号

I have tow number float

float a = 3741164032f;
float b = 3741163983f;
float c = a-b;
System.out.printf("%f",a);

而且我不知道为什么c = 0.

And i don''t unknow why c =0.

推荐答案

float数据类型精确到24位，大约是大约小数点后7位.因此，您的两个电话号码均为3.741164e9.
如果使用double，此问题将得到缓解.如果需要准确，更好的方法是使用long或 [^ ].

The float data type is accurate to 24 bits which is about 7 decimal places. So both of your numbers will be 3.741164e9.
If you used double this problem would be alleviated. Better if you need to be exact would be to use either long or BigDecimal[^].

很遗憾，这是浮点类型的精度.为什么不使用整数类型作为示例?它将为您带来预期的结果.

—SA

Unfortunately, this is the accuracy of float type. Why not using integer type for your example? It would give you the result you expected.

—SA

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