在下一个方法中测试异常 [英] Test for Exception in next Method

问题描述

在Method2中是否可以测试Method1中是否存在异常?
(彼此调用:Method1-> Method2)

只是知道是否有一个?

Is there a Way to test in a Method2 if there was a Exception in Method1?
(Called after each other: Method1 --> Method2)

Just to know if there was one?

推荐答案

测试任何异常情况是对该技术的大滥用.放开异常.

该怎么办?请在我过去的答案中找到一些建议:
我如何制作滚动条到达底部时将停止的循环 [当我运行应用程序时，异常是捕获了如何处理? [ throw. .then ... rethrowing [ ^ ].

-SA

Testing anything for exceptions is a big abuse of the technology. Let exceptions go.

What to do? Please find some recommendations in my past answers:
How do i make a loop that will stop when a scrollbar reaches the bottom[^],
When i run an application an exception is caught how to handle this?[^],
throw . .then ... rethrowing[^].

—SA

以防万一您在Method2中捕获到异常并在处理后将其扔回.
这样的东西

In case you catch the exception in Method2 and after processing throw it back.
Something like this,

sub method1()
{
 try
 {
  method2();
 }
 catch(exception ex)
 { 
  ...
 }
}
sub method2()
{
 try
 {
  ...
 }
 catch(exception ex)
 { 
  ...
  throw ex;
 }
}

您始终可以通过代码查看stacktrace.有关更多信息，请参见此处 [

You can always look at the stacktrace via code. For more information, see here[^].

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