如何抛出异常到下一个捕获? [英] How to throw exception to next catch?

问题描述

我想在下一个捕获时抛出异常，(我附有图片)

I want to throw an exception at next catch, (I attached image)

有人知道该怎么做吗?

推荐答案

您不能这样做，这表明您在catch块中逻辑太多，或者应该重构方法只做一件事情.如果无法重新设计，则必须嵌套try块:

You can't, and trying to do so suggests that you've got too much logic in your catch blocks, or that you should refactor your method to only do one thing. If you can't redesign it, you'll have to nest your try blocks:

try
{
    try
    {
        ...
    }
    catch (Advantage.Data.Provider.AdsException)
    {
        if (...)
        {
            throw; // Throws to the *containing* catch block
        }
    }
}
catch (Exception e)
{
    ...
}

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