如何解决与C语言相关的问题? [英] How to solve this problem Related to C language?

问题描述

#include<conio.h>
#include<stdio.h>
void main()
{
clrscr();
int num=20;
printf("\t%d",&num);
getch();
}

在TC 16位编译器上运行程序时，输出为-12.
我不知道变量num的地址怎么可能是-12，即负数.
等待答案....
问候

here the output which I get is -12 when I run the program on TC 16bit compiler.
I wan''t to know how come the address of a variable num can be -12,a negative number.
waiting for the answer....
regards

推荐答案

内存地址不是带符号的整数.符号取决于最高位.
对于16 bit， 0x8000及更高版本地址将为负，并且对于32 bit上的0x80000000同样.

希望对您来说清楚.

Memory addresses are not signed integers. The sign depends on the highest bit.
For 16 bit, 0x8000 and above addresses would be negative and same is for 0x80000000 on 32 bit.

I hope it is clear for you.

尝试将其打印为unsigned整数

Try printing it as an unsigned integer

printf("\t%u",(unsigned int)&num);

因为应该正确使用格式说明符(printf根据格式说明符解释其参数).
由于&num是内存地址，因此应使用%p，即:

Because format specifiers should be used wisely (printf interprets its arguments based on format specifiers).
Since &num is a memory address, you should use %p, namely:

printf("\t%p",&num);

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