如何从6位数字中取出最后两个数字 [英] how take last two number from 6digit number

问题描述

hi
在我的项目中，我随机显示支票号码
像random.next(100000,999999)一样会随机提供一些值，例如234567
在那我应该选择最后两位数字并设置支票号码范围为1到10
(234568至234578)之类的人可以帮助我


在此先感谢
pallavi

hi
in my project i am displaying cheque number randomly
like random.next(100000,999999) it will give some value randomly like 234567
in that i should select last two digits and set cheque number range from 1 to 10
like (234568 to 234578) can any one help me for how to do this


thanks in advance
pallavi

推荐答案

我无法理解您所写内容的全部内容.尽管这是从数字中获取最后两位数字的方法:

I am not able to understand complete thing what you have written. Although this is how you can get the last two digits from a number:

int lastTwoDigits = number % 100;

您可以对100做模以得到最后2位数字.

You can simply do modulo 100 to get the last 2 Digits.

int a = 123456789
int b = a % 100
Console.WriteLine("b: ",b);

输出:
b = 89

Output :
b = 89

我的意思是您想更改最后两个数字，例如，如果它们是12，那么您想将其改为22吗?

无论如何，我都会认为答案是正确的:-D

所以这里是

您所要做的就是在您的电话号码中加1 :-)

123456 + 1 = 123457，这是来自

并添加11到

123456 + 11 = 123467，这是

这是你的范围

希望我能帮忙
:-)

I think you mean that you want to to change your last 2 numbers for example if they are 12 you want them to be 22 right?

I will assume the answer is right anyway :-D

so here it is

all you have to do is to add 1 to your number :-)

123456 + 1 = 123457 and here is the from

and add 11 to it too

123456 + 11 = 123467 and here is to

and here is your range

I hope I helped
:-)

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