生成随机的6位数字 [英] Generate random 6 digit number

问题描述

我已经搜索了几个小时，但似乎找不到这个问题的答案.我想生成一个6位数字的随机数.你们当中有些人可能会告诉我使用以下代码:

I've been searching for a couple of hours and I just can't seem to find a answer to this question. I want to generate a random number with 6 digits. Some of you might tell me to use this code:

        Random generator = new Random();
        int r = generator.Next(100000, 1000000);

但是那限制了我的6位数字的总和必须超过100000.我希望能够使用000 001、000 002等生成一个int.稍后我希望将该整数转换为字符串.

But that limits my 6 digits to all be above 100 000 in value. I want to be able to generate a int with 000 001, 000 002 etc. I later want to convert this integer to a string.

推荐答案

如果您希望字符串以零开头，请尝试此操作.您无法获得001之类的整数.

If you want a string to lead with zeroes, try this. You cannot get an int like 001.

    Random generator = new Random();
    String r = generator.Next(0, 1000000).ToString("D6");

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