我需要更改三联代码 [英] c++ i need to change tripple code

问题描述

#include <iostream>
using std::cout;
using std::endl;

#include <iomanip>
using std::setw;

#include <cmath>
using std::sqrt;

int main()
{
    const int N = 6;
    for (int i = 2; i <= N; ++i)
        for (int j = 1; j < i; ++j)
            for (int k = 0; k < j; ++k)
                cout << "(" << k << "," << j << "," << i << ")" << endl;
    return 0;
}

输出为:
(0,1,2)
(0,1,3)
(0,2,3)
(1,2,3)
.
.
.
(1,5,6)
(2,5,6)
(3,5,6)
(4,5,6)

我需要更改代码以显示以下内容:
2 1
3 4
4 10
5 20
6 35
7 56
8 84
9120
10165

右边的数字是三组的数字，以左边的数字结尾

谢谢

The output is:
(0,1,2)
(0,1,3)
(0,2,3)
(1,2,3)
.
.
.
(1,5,6)
(2,5,6)
(3,5,6)
(4,5,6)

I need to change the code to show the below:
2 1
3 4
4 10
5 20
6 35
7 56
8 84
9 120
10 165

Right number is the number of triple set which ends with left number

thank you

推荐答案

在代码中添加列表或数组，并在循环中对项目进行计数，然后在最后打印结果.例如:

Add a list or array to your code and count the items as you go through your loop and then print the results at the end. So for example:

int list[10];
int index;
...
index = ???;  // where ??? is the ending number
list[index] += 1;

最后，只需迭代您的列表即可打印所有非零的总数.

At the end just iterate your list printing all the non-zero totals.

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