获取TreeView中的所有最后一个节点. [英] Get all the last node in a TreeView.

问题描述

大家好；

我有一个有很多节点的树视图，有没有办法让我得到树所具有的每个节点中的所有最后一个节点?

谢谢.

Hi Everyone;

I have a treeview that has a lot of nodes, Is there a way I can get all the last nodes in each node that the tree has?

Thanks.

推荐答案

我知道的唯一方法是从TreeView本身的Nodes集合开始，然后递归地访问，或者以其他方式访问其Nodes集合.依此类推........然后使用Nodes[Nodes.Count - 1]来获取每个节点的最后一个节点.

The only way I know is to start with the Nodes collection of the TreeView itself and then recursively or otherwise visit its Nodes collection and so on..... then use Nodes[Nodes.Count - 1] to get the last node for each one.

可以给我一个例子吗?我尝试了这段代码，但没有返回最后一个节点.

Can you please give me an example? I tried this code but it didn''t return the last node.

ArrayList ae = new ArrayList();

for (int iCount = 0; iCount < mytreev.nodes.Count; iCount++)
        {


ae.Add(nodes[nodes.count-1].LastNode.Text)

}

看看

Take a look at this[^] thread.

The 4th entry has a code example (it''s in VB.net but should be easy enough to understand)

Incidentally in your code:

ae.Add(nodes[nodes.count-1].LastNode.Text)

我不知道您从哪里获得LastNode属性.据我所知，没有这样的财产.应该是:

I don''t know where you have got the LastNode property from. As far as I know, there is no such property. It should be:

ae.Add(nodes[nodes.count-1].Text)

如果您将上面链接中的方法与从此处 [ ^ ]，您应该能够解决问题.

If you combine the method from the link above with the example of iterating the Nodes of a TreeView from here[^] on MSDN, you should be able to work out a solution.

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