访问 TreeView 控件中的所有节点 [英] Accessing all the nodes in TreeView Control

问题描述

我有一个带有一组节点和子节点的 TreeView 控件.例如:

I have a TreeView Control with set of nodes and child nodes. For example:

ROOT 有 A、B、C.

ROOT has A,B,C.

A 有 a1、a2、a3，然后 a1、a2 还包含一些节点，如 x1、x2、x3 等.像这样有很多子节点.我知道可以在 for 循环中使用循环.

A has a1, a2, a3 and then that a1, a2 also contains some nodes like x1, x2, x3 and so on. Like this many subnodes are there. I know it is possible to use loops with a for loop.

我只想使用一两个 for 循环访问 TreeView 控件中的所有节点.

I just want to access all the nodes in TreeView control using one or two for loops.

是否有任何算法或其他方法?

Is there any algorithm for that or is there any other way?

再问一个问题:是否可以使用任何库函数在对象或字符串中获得树节点的路径?例如:

One more question: Is it is possible to have the path of a tree node in an object or in a string using any library functions? For example:

string S = TreeView1.Nodes[i].Nodes[j].Nodes

推荐答案

不要使用嵌套循环，而是使用递归解决方案，例如:

Don't use nested loops, but go for an recursive solution like:

void ListNodes( TreeNode node )
{
  foreach( var subnode in node.Nodes )
  {
    ListNodes( subnode );
  }
  // Print out node
}

为您的根节点调用此函数.

Call this function for your root node.

对于您的其他问题:检查 FullPath 属性.

For your additional question: check the FullPath property.

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