在访问TreeView控件的所有节点 [英] Accessing all the nodes in TreeView Control
问题描述
我有一组节点和子节点的 TreeView控件
控制。例如:
ROOT有A,B,C
块引用>
$。 b $ b一个具有A1,A2,A3,然后将该A1,A2中还包含像X1,X2,X3和等一些节点。很多这样子节点的存在。我知道这是可能使用循环使用循环。
我只是想访问
TreeView控件
使用一个或两个for循环的控制。
有任何算法为或有任何其他方式?
还有一个问题:它可能有一个对象,或使用任何库函数字符串树节点的路径?例如:
串S = TreeView1.Nodes [I] .Nodes [J] .Nodes
解决方案不要使用嵌套的循环,但去像一个递归解决方案:
无效ListNodes(TreeNode的节点)
{
的foreach(在node.Nodes VAR子节点)
{
ListNodes(子节点);
}
//打印出点
}
调用此。功能为您的根节点
有关的另一个问题:检查
完整路径
属性I have a
TreeView
Control with set of nodes and child nodes. For example:ROOT has A,B,C.
A has a1, a2, a3 and then that a1, a2 also contains some nodes like x1, x2, x3 and so on. Like this many subnodes are there. I know it is possible to use loops with a for loop.
I just want to access all the nodes in
TreeView
control using one or two for loops.Is there any algorithm for that or is there any other way?
One more question: Is it is possible to have the path of a tree node in an object or in a string using any library functions? For example:
string S = TreeView1.Nodes[i].Nodes[j].Nodes
解决方案Don't use nested loops, but go for an recursive solution like:
void ListNodes( TreeNode node ) { foreach( var subnode in node.Nodes ) { ListNodes( subnode ); } // Print out node }
Call this function for your root node.
For your additional question: check the
FullPath
property.这篇关于在访问TreeView控件的所有节点的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!