在显示argc和argv时需要帮助 [英] Need help with displaying argc and argv

问题描述

我在Linux上运行以下代码:

I run the following code on Linux:

#include <stdio.h>
#include <string.h>
int main( int argc, char ** argv )
{
    int I_count;
    for( I_count = 0; I_count < argc; I_count++ )
    {
            fputs( argv[I_count], stdout );
    }
    putchar( '\n' );
    return 0;
}

并在终端窗口中获​​得此结果:
输入:./1 jiawei

输出:./jiawei

我不明白为什么，如果您知道，请回答我.谢谢.

And get this result in terminal window:
Input: ./1 jiawei

Output: ./jiawei

I don''t understand why, if you know please answer me. Thanks.

推荐答案

我想程序输出实际上是:

I suppose the program output is actually:

./1jiawei

因为您没有在打印的参数之间放置任何分隔符.
试试

since you didn''t put any separator between the printed arguments.
Try

...
    for( I_count = 0; I_count < argc; I_count++ )
    {
            fputs( argv[I_count], stdout );
            fputs( " ", stdout);
    }
...

:)

:)

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