在 C++ 中解析 argc 和 argv [英] parsing argc and argv in c++

问题描述

我想学习更多 C++... 通常我会创建一个 for 循环来解析 argv，最后我会得到一堆 C 风格的字符串.我想在 C++ 中做类似的事情，但最好不要从/proc/whatever 中读取.起初，我试图将 C 风格的字符串转换为 C++ 风格的字符串而没有结果......令人沮丧的是，SO 上的每个人似乎都想知道如何走另一条路，这就是 c_str() 的用途.这样做的好 C++ 方法是什么(即解析 argv)?

I want to learn more C++... Usually I make a for loop to parse argv, and I wind up with a bunch a C-style strings. I want to do something similar in C++, but preferably without reading from /proc/whatever. At first, I tried to convert the C-style string to a C++ style string without results... The frustrating bit is that everyone on SO seems to want to know how to go the other way, which is what c_str() is for. What's a good C++ way to do this (ie parse argv)?

另外，请注意，我正在寻找一个 Unix 风格的答案，我所见过的所有转换技术都与 Windows 相关，我完全不了解它.

Also, one note, I'm looking for a unix style answer, all the techniques for conversion I've seen have to do with Windows, which I'm completely uniterested in.

推荐答案

我不确定我是否完全理解这个问题.

I'm not sure I fully understand the question.

我知道在一个易于使用的数组中获取所有参数的最干净的方法是:

The cleanest method I know to get all the arguments in an easy to use array is:

std::vector<std::string> v(argv, argv + argc);

但如果您正在寻找一种真正解析数据的方法，请查看 Boost.ProgramOptions.

But if you're looking for a way to really parse the data, check out Boost.ProgramOptions.

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