什么是20号这个系列中的3,18,52,132 ............ [英] what is the 20 th no. of this series 3,18,52,132.............

问题描述

第20号是什么.这个系列中的3,18,52,132 ............. ??

请尽快将答案发送给我:(


谢谢:)

what is the 20 th no. of this series 3,18,52,132.............??

plz send me the answer as soon as posble :(


thanks :)

推荐答案

我们不做作业问题，当然也不是尽快.

但是，取3，加倍再加上12，得到18
18，加倍加16(大于12的四个)，得到52
将其加倍，再加上20(大于16的四个)，得出132
沿着那条线继续，直到第20次迭代产生10485668.

假设迭代跳跃是正确的.

[来自WW]
我正在尝试遵循您的数学要求，但并没有加总.
3 * 2 + 12 = 18 *正确
18 * 2 + 16 = 52 *正确
52 * 2 + 20 = 124 *不正确

该版本的第20次迭代将是9961380.

他再次发布了问题，发现有人: http://www.research.att.com/~njas/sequences /A061317 [ ^ ]其中显示解决方案.

We don''t do homework questions, and certainly not ASAP.

However, take 3, double it and add 12 to give 18
18, doubled add 16 (four more than 12) to give 52
Double it, add 20 (four more than 16) to give 132
Continue along that line to yield 10485668 as the 20th iteration.

Assuming that the iteration jumps are correct.

[From WW]
I''m trying to follow your math, but it doesn''t add up.
3*2 + 12 = 18 *correct
18*2 + 16 = 52 *correct
52*2 + 20 = 124 *incorrect

The 20th iteration of that would be 9961380.

He posted the question again and someone found: http://www.research.att.com/~njas/sequences/A061317[^] which shows a solution.

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