Console.WriteLine("args [{0}] = [{1}]"，i，args [i]) [英] Console.WriteLine("args[{0}]=[{1}]", i, args[i])

问题描述

public class CommandLine
{
    public static void Main(string[] args)
    {
        Console.WriteLine("Number of command line parameters={0}", args.Length);
        Console.ReadKey();
        for (int i = 0; i < args.Length; i++)
        {
            Console.WriteLine("args[{0}]=[{1}]", i, args[i]);


        }
    }
}

任何人都可以简要解释一下代码中加粗的部分到底是做什么的吗?

Can any one briefly explain what exactly does the bolded part of the code do???

推荐答案

它返回通过"args"提供的每个参数...只需运行代码])

It returns every single parameter provided via "args"... Just run the code ;)

我只是希望这不是您的任务之一！

粗体部分是一个接一个地处理参数，然后将其打印出来，格式为...
args [0] =某物
args [1] =某物
....

必须非常清楚...一旦执行程序...或仅对其进行调试！

I just hope this is not one of your assignments!

The bold part is taking the arguments one by one and printing that off... in a format like...
args[0] = something
args[1] = something
....

Must be quite clear...once you execute the program... or just debug it!

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