如何将十六进制字符串转换为浮点值 [英] How Do I Convert Hex String To Float Value

问题描述

我有一个十六进制字符串="41BD9A69"，我需要将此十六进制字符串转换为ASCII十六进制IEEE Float.
我的意思是我们如何以编程方式在C ++中或使用库将此十六进制字符串转换为等效的float值23.700396.
十六进制字符串="41BD9A69" = 23.700396

I have a Hex String = "41BD9A69", I need to convert this hex string into ASCII Hex IEEE Float.
I meant how do we convert this hex string into equivalent float value of 23.700396 programatically in C++ or using library.
Hex String = "41BD9A69" = 23.700396

推荐答案

您可以使用联合技巧:

You might use the union trick:

#include <iostream>
#include <sstream>
#include <iomanip>
using namespace std;

union ulf
{
    unsigned long ul;
    float f;
};

int main()
{
    ulf u;
    string str = "41BD9A69";
    stringstream ss(str);
    ss >> hex >> u.ul;
    float f = u.f;
    cout << f << endl;
}

它并不复杂，但请看这里: http ://gregstoll.dyndns.org/~gregstoll/floattohex/ [ ^ ]-它是一个计算器模块，其中包括C源代码即可做到这一点.

It''s not complex, but look here: http://gregstoll.dyndns.org/~gregstoll/floattohex/[^] - it''s a calculator module, that includes C source to do just that.

这应该可以解决您的问题

This should solve your problem

float f;
long l;

l = strtol(HEXString, (char**)NULL, 16);
f = (float)l;

printf("%f", f);

请参阅下面的详细说明

在c中将十六进制转换为浮点数，反之亦然 [ ^ ]

See below for detail explanation

Convert a hexadecimal to a float and viceversa in c[^]

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