提取特定的字符串整型 [英] extract specific string & int

问题描述

我有列表"变量，其中包含--ASW+90s, 160, 160S, M45s, 130.5. R+129.
之类的值
我想知道如何提取字符串，例如160s和R + 129.
到目前为止，这是我的尝试，但是我一直遇到编译错误:

I have ''list'' variable, which contains values such as - ASW+90s, 160, 160S, M45s, 130.5. R+129.

I would like to know, how can I extract strings such as 160s and R+129.
Here is my attempt so far, but I keep experiencing compiling errors:

else if (Int32.TryParse(list, out i))
                               {
                                   string b = "";
                                   b += list == "S";
                                   if (Math.Abs(i) >= 125 && b)
                                   {
                                       string a = "";
                                       a += i.ToString();
                                       row["Value"] = a;
                                   }
                               }

如果有人可以帮助定义，则进一步执行此任务所需的逻辑将对继续前进有很大帮助.

任何帮助，不胜感激.
谢谢

if someone could help to define, the logic required to implement this task further, that would be a great help, to progress forward.

Any help much appreciated.
Thanks

推荐答案

在这里:

var str = "ASW+90s, 160, 160S, M45s, 130.5, R+129";
var list = str.Split(new string[] {", "}, StringSplitOptions.RemoveEmptyEntries);

var re1 = new Regex(@"^[A-Za-z]\+\d+

")； var re2 = 新正则表达式( @" ^(\ d +)[sS]

"); var re2 = new Regex(@"^(\d+)[sS]

"); var 结果= 来自元素 列表中的元素 让 m2 = re2.Match(element) 其中 re1.Match(element).Success || (m2.成功&& int .Parse(m2.Groups [ 1 ].Value)> 125 ) 选择元素； result.Dump();

"); var result = from element in list let m2 = re2.Match(element) where re1.Match(element).Success || (m2.Success && int.Parse(m2.Groups[1].Value) > 125) select element; result.Dump();

这不是纯正则表达式，因为我将语义验证用于第二个条件.并且它正在处理具体的列表/数组，但是如您所见，将字符串拆分为列表/数组非常简单.

This is not pure-regexp, as I am using semantic validation for the second criteria. And it is working on a concrete list/array, but as you can see it is quite simple to split the string into a list/array.

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