在bash特定子字符串后提取令牌 [英] Extract token after particular substring in bash

问题描述

假设我有一个bash脚本包含几行的字符串变量：

Suppose I have a string variable in a bash script that contained several lines:

blah blah blah
...
...
an interesting parameter: 12345 some other useless stuff...
...
...

我想从这个字符串中提取12345。我试图寻求新的方式使用'一个有趣的参数：'作为一个分隔符，但我不能完全得到它的工作。是否有这样做的一个干净的方式？

I want to extract 12345 from this string. I have tried to look for ways to use 'an interesting parameter:' as a "delimeter" but I couldn't quite get it to work. Is there a clean way of doing this?

推荐答案

庆典支持正前pression匹配，而无需使用外部程序。

bash supports regular expression matching without using external programs.

$ str='
blah blah blah
...
...
an interesting parameter: 12345 some other useless stuff...
...
...'
$ [[ $str =~ an\ interesting\ parameter:\ ([[:digit:]]+) ]]

$ echo ${BASH_REMATCH[1]}
12345

阵列 BASH_REMATCH 包含元素0和捕获的分组全场比赛（左到右的顺序）在随后的元素。

The array BASH_REMATCH contains the full match in element 0 and the captured subgroups (in left-to-right order) in subsequent elements.

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