用bash解析字符串并提取数字 [英] Parse string with bash and extract number

问题描述

我有主管的状态输出，看起来像这样.

I've got supervisor's status output, looking like this.

frontend                         RUNNING    pid 16652, uptime 2:11:17
nginx                            RUNNING    pid 16651, uptime 2:11:17
redis                            RUNNING    pid 16607, uptime 2:11:32

我需要提取nginx的PID.我已经通过grep -P命令完成了此操作，但是在远程计算机上grep的构建没有perl正则表达式的支持.

I need to extract nginx's PID. I've done it via grep -P command, but on remote machine grep is build without perl regular expression support.

看起来sed或awk正是我所需要的，但是我并不熟悉它们.

Looks like sed or awk is exactly what I need, but I don't familiar with them.

在此先感谢您帮助我找到一种方法.

Please help me to find a way how to do it, thanks in advance.

推荐答案

sed 's/.*pid \([0-9]*\).*/\1/'

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