python中的三元运算符 [英] Ternary operator in python

问题描述

先生，我在python中使用三元运算符时遇到问题.

我在C/C ++中使用了三元运算符，例如C

Sir, I have a problem with ternary operator in python.

I have used the ternary operator in C/C++ e.g for C

int a = (5>9)? 2 : 3

就像这样

在这里，a的值被指定为3.

我像这样在python中尝试了相同的方法

it comes like this

Here the value of a is assigned to be 3.

I tried the same in python like this

>>>> a=5>9if 3 else 7
>>> print(a)

这里的输出为"False"，所以我发现我的代码有零个错误，但输出为布尔值.

然后我像这样打字我的代码，

here the output comes "False" so I found that my code has zero errors but the output is in Boolean.

Then I typecast-ed my code like this,

>>>> a=int(5>9)if 3 else 7
>>> print(a)

输出为"0"，这让我感到奇怪.

所以，我尝试过这样，

Here the output comes "0" which made me to wonder.

So, I tried like this,

>>> a=int(5>9)if int(3) else int(7)
>>> print(a)

但是输出仍然为零. python中有什么方法可以使用三元运算符.

我错过了什么吗?

请帮助我.谢谢.

But still the output is zero. Is there any way in python to use a ternary operator.

Have I missed anything?

Kindly help me with this.Thank you.

推荐答案

在Python中是:
如果5> a = 2，则a = 2. 9其他3

希望对您有所帮助.

In Python it is:
a = 2 if 5 > 9 else 3

I hope it helps.

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