在C编程中将Fputc二进制转换为ASCII [英] Fputc binary to ascii in C programming

问题描述

嗨朋友
我有一个用c语言编写的文件，该文件包含二进制字节，意味着只有0和1！
我想将每8个字节收集为ASCII并保存在另一个文件中！
谢谢

我尝试过的事情:

 bit_files * tmp;
tmp =(bit_files *)malloc( sizeof (bit_files));
字符 a;
FILE * first_file，* final_file;
first_file = fopen(" ，"  r")；
final_file = fopen(" ，"  w")；

            tmp-> bitBuffer<< =  1 ;
            tmp-> bitCount =  0 ;

 while (a = fgetc(first_file)！= EOF)
{
如果(a ==  0 )
{
tmp-> bitBuffer = tmp-> bitBuffer<< =  1 ;
}
其他
{
tmp-> bitBuffer = tmp-> bitBuffer | =  1 ;
}
tmp-> bitCount ++;
如果(tmp-> bitCount ==  8 )
{
fputc(tmp-> bitBuffer，final_file);
tmp-> bitBuffer =  0 ;
tmp-> bitCount =  0 ;
}
}
fclose(first_file);
fclose(final_file); 

解决方案

二进制文件"不只包含零和1，还包含二进制数据-未签名的char每个值包含0到255之间(含0和255)的值.如果您的数据确实是每个字节仅二进制值0和1，那么您所要做的就是使用<<循环遍历无符号字符中的每个八位.运算符，将每个位移到适当位置，然后在完成后将每个组合字节写入输出中.

但是我首先要使用十六进制编辑器查看您的二进制文件，以确保您不仅误解了整个应用程序！

一种更简单的方法是读取八个字节一次并从低阶位组合ascii，例如:

  char  inputBuffer [ 8 ];
字符 temp;
FILE * binin;
 int  i;

binin = fopen(" ，"  rb")；
如果(binin == NULL)
    exit( 1 );
做
{
     int  nIn = fread(inputBuffer， sizeof ( char )， sizeof  inputBuffer，binin)；
    如果(nIn<  sizeof  inputBuffer)
     break ;
    temp =  0 ;
     for (i =  0 ; i<  8 ; ++ i)
    {
        temp | =(inputBuffer [i]&  1 )<< ( 7 -i)；
    }
    printf(" ，临时)；
} 同时( 1 )；
printf(" ); 

hi friends
i have a file in c langage , this file contatins binary byte it means only 0 and one !
i want to collect every 8 bytes to ASCII and save in another file !
thank you

What I have tried:

bit_files *tmp;
tmp = (bit_files *)malloc(sizeof(bit_files));
char a;
FILE *first_file,*final_file;
first_file=fopen("file1","r");
final_file=fopen("file2","w");
		
            tmp->bitBuffer <<= 1;
            tmp->bitCount = 0;
			
while (a=fgetc(first_file)!=EOF)
{
	if (a==0)
	{
	tmp->bitBuffer=tmp->bitBuffer<<=1;
	}
	else
	{
		tmp->bitBuffer=tmp->bitBuffer|=1;
	}
	tmp->bitCount++;
	if (tmp->bitCount==8)
	{
		fputc(tmp->bitBuffer,final_file);
		tmp->bitBuffer=0;
		tmp->bitCount=0;
	}
}
fclose(first_file);
fclose(final_file);

解决方案

A "binary file" doesn''t contain just zero and 1, it contains binary data - which are unsigned char values each containing between 0 and 255 inclusive. If your data truly is the binary values 0 and 1 only per byte, then all you need to do is loop through collecting each eight bits in an unsigned char by using the << operator to move each bit up into place and then write each assembled byte to your output when it''s finished.

But I''d start by looking at your binary file with a hex editor to make sure you aren''t just misthinking the whole app!

A simpler way would be to read eight bytes at a time and assemble the ascii from the low order bits, something like:

char			inputBuffer[8];
char			temp;
FILE*			binin;
int				i;

binin = fopen("ctest.txt", "rb");
if (binin == NULL)
    exit(1);
do
{
    int nIn = fread(inputBuffer, sizeof(char), sizeof inputBuffer, binin);
    if (nIn < sizeof inputBuffer)
    break;
    temp = 0;
    for (i = 0; i < 8; ++i)
    {
        temp |= (inputBuffer[i] & 1) << (7 - i);
    }
    printf("%c", temp);
} while(1);
printf("\n");

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