在Java中将小数转换为二进制 [英] Converting decimal to binary in Java

问题描述

我想写一个将数字转换为二进制的代码，这就是我写的。它给我几个Eclipse中的错误，我不明白。
这是什么问题？任何其他建议？我想学习和听到任何意见，修复它。谢谢。

I'm trying to write a code that converts a number to binary, and this is what I wrote. It gives me couple of errors in Eclipse, which I don't understand. What's wrong with that? Any other suggestions? I'd like to learn and hear for any comments for fixing it. Thank you.

public class NumberConverte {
  public static void main(String[] args) {
    int i = Integer.parseInt(args);
    public static void Binary(int int1){
      System.out.println(int1 + "in binary is");
      do {
        System.out.println(i mod 2);
      } while (int1>0);
    }
  }
}

错误消息：

1. 方法 parseInt（String）在类型 Integer 不适用于参数（ String [] ）


2. 此行有多个标记
   
   
   
   • 令牌上的语法错误（，
   
   ），;预期
   
   • void 是变量的无效类型 Binary
   
   

1. The method parseInt(String) in the type Integer is not applicable for the arguments (String[])
2. Multiple markers at this line
   • Syntax error on token "(", ; expected
   • Syntax error on token ")", ; expected
   • void is an invalid type for the variable Binary

• 令牌mod的语法错误，无效AssignmentOperator


• 令牌mod的语法错误，无效的AssignmentOperator。

推荐答案

Integer.toBinaryString（int）应该做的！

顺便说一下，纠正你的语法，如果你使用Eclipse我相信他抱怨很多错误。

And by the way, correct your syntax, if you're using Eclipse I'm sure he's complaining about a lot of error.

工作代码：

public class NumberConverter {
   public static void main(String[] args) {
       int i = Integer.parseInt(args[0]);
       toBinary(i);
   }

   public static void toBinary(int int1){
       System.out.println(int1 + " in binary is");
       System.out.println(Integer.toBinaryString(int1));
   }
}

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