如何创建适当的JAXB映射以使Jersey反序列化过程发生 [英] How to create proper JAXB mapping to make Jersey deserialization process happened

问题描述

我有来自WS的JSON响应:

I have JSON response from WS:

[
  {
    "name": "Bobby",
    "status": "single"
  },
  {
    "name": "John",
    "status": "married"
  }
]

这是我的包装纸

@XmlRootElement(name = "users")
public class UserListWrapper {   

    private List<User> users;   

    @XmlElement(name = "user")
    public List<User> getUsers() {
        return users;
    }    

    // getters and setters omitted
}

和用户类别

@XmlRootElement
class User {
    private String name;
    private String status;    

    // getters and setters omitted
}

问题是当Jersey尝试反序列化对我的包装器对象的响应时.它说

The problem is when Jersey try to deserialize response to my wrapper object. It say

Caused by: org.codehaus.jackson.map.JsonMappingException: Can not deserialize instance of com.jersey.test.UserListWrapper out of START_ARRAY token

表明我的包装器注释出了点问题.我该如何解决?

Seams that something wrong with my wrapper annotations. How can I fix them?

UPD

我发送

{
  "user": [
    {
      "name": "Bob",
      "status": "single"
    },
    {
      "name": "Mike",
      "status": "married"
    }
  ]
}

一切正常.但是我需要这种格式

all works fine. But I need this format

[
  {
    "name": "Bobby",
    "status": "single"
  },
  ...
]

UPD

Jersey客户代码

Jersey Client code

    HttpAuthenticationFeature authenticationFeature = HttpAuthenticationFeature.basic("user", "secret");
    Client client = ClientBuilder
            .newClient()
            .register(authenticationFeature)
            .register(JacksonFeature.class);

    WebTarget target = client.target("http://localhost:8080/server/");
    UserListWrapper entity;
    Response resp;

    resp = target.queryParam("u", "info")
            .path("/rest/users")
            .request()
            .accept(APPLICATION_JSON)
            .get();


    entity = resp.readEntity(UserListWrapper.class);

推荐答案

然后忘记UserListWrapper包装器. List<User>非常适合JSON数组([])格式.如果添加包装器类，则是的，您将需要额外的JSON对象层({}).这个:

Forget the UserListWrapper wrapper then. List<User> is perfect for the JSON array ( [] ) format. If you add the wrapper class, then yes you will need the extra JSON object layer ( {} ). This:

@POST
@Consumes(MediaType.APPLICATION_JSON)
public Response createBook(List<User> users) {

受到很好的支持(至少使用杰克逊-您正在使用).

is supported just fine (at least with Jackson - which you are using).

更新

如果来自服务器的响应以JSON数组的形式出现，那么您仍然可以将其反序列化为List<User>.例如

If the response from the server is coming as a JSON array, then you can still deserialize it as a List<User>. For example

WebResource resource = client.resource("...");
List<User> users = resource.get(new GenericType<List<User>>(){});

请参阅此相关文章

更新2

由于使用的是JAX-RS 2客户端API，因此可以使用重载的

Since you are using the JAX-RS 2 client API, you can use the overloaded readEntity, which accepts a GenericType argument also

List<User> user = response.readEntity(new GenericType<List<User>>(){});

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