用正则表达式将Jenkins职位排除在外 [英] Exclude Jenkins jobs from view with regular expression

问题描述

我们在Jenkins的视图中使用正则表达式包含作业. 目前，示例"视图的正则表达式为example_(.+).

We're using regular expressions to include jobs in our views for Jenkins. At the moment the regular expression for the "example"-view is example_(.+).

但是，我们刚刚添加了一个名为"example_example2"的新项目，现在该项目的作业也出现在示例"视图中. 是否有任何正则表达式从"example"视图中排除"example_example2" -job?我一直在尝试使用^，但没有成功.

However we just added a new project called "example_example2" and now the jobs from this project also appear in the "example" view. Is there any regular expression to exclude the "example_example2"-jobs from the "example"-view? I have been trying to use ^ but no success.

你能帮帮我吗?

推荐答案

您可以将example_而不是example2后面跟在字符串位置的末尾(使用负前瞻)进行匹配:

You may match example_ not followed with example2 followed with the end of string position using a negative lookahead:

example_(?!example2$)(.+)
        ^^^^^^^^^^^^^

如果需要锚定样式，请在开始处添加^. .+将匹配换行符以外的任何1个或多个字符，直到行尾为止.

In case you need to anchor the pattern add ^ at the start. .+ will match any 1 or more characters other than line break chars up to the end of the line.

在线查看 regex演示.

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