如何在泽西岛注册静态课程? [英] How to register a static class in Jersey?

问题描述

我有一类只能通过@path批注访问静态方法的类，并且没有公共构造函数.我的简化程序是:

I have a class of which only static methods are to be accessed via @path annotations and which does not have a public constructor. My simpilified program is:

@Path("")
static class MyStaticClass
{
  private MyStaticClass() {...}
 @Get @Path("time")
  static public String time()
  {
     return Instant.now().toString();
  }
}

运行并调用时间"会给我以下错误:

Running and calling "time" gives me the following error:

WARNUNG: The following warnings have been detected: WARNING: HK2 service reification failed for [...] with an exception:
MultiException stack 1 of 2
java.lang.NoSuchMethodException: Could not find a suitable constructor in [...] class.

推荐答案

对不起，根据

Sorry, according to the JSR, paragraph 3.1.2

根资源类由JAX-RS运行时实例化，并且必须 有一个公共构造函数，JAX-RS运行时可以为其提供所有 参数值.请注意，零参数构造函数是允许的 在这个规则下.

Root resource classes are instantiated by the JAX-RS runtime and MUST have a public constructor for which the JAX-RS runtime can provide all parameter values. Note that a zero argument constructor is permissible under this rule.

您可以使用适配器设计模式并创建JAX-RS资源(带有@Path的POJO )，它只是委托给您的静态类.对于那些在你身后的人来说，这很容易理解.

You can use the Adapter design pattern and create JAX-RS resource (POJO with @Path) which simply delegates to your static class. This would be very easy to understand for those coming behind you.

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