REST:将通过POST传递的XML内容转换为Java对象,该元素内部的属性 [英] REST: convert XML content passed with POST to a java object, attribute inside the element

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问题描述

我正在使用REST服务,我想通过POST请求传递XML文本.我的服务器是用JAVA实现的.假设我正在发送此XML:

I am working with REST services and i want to pass an XML-text with a POST request. My server is implemented in JAVA. Let's say that i am sending this XML:

<range>
  <higher value="3"></higher>
  <lower value="2"></lower>
</range>


据我了解(如果我做错了,请纠正我),将请求中的XML转换为Java对象的最简单方法是定义带有适当注释的类.例如:


As i understand (correct me if i am wrong), the easiest way to convert the XML in the request to a java object, is to define a class with the proper annotations. For example:

@XmlRootElement(name = "range")
public class RangeClass {

    @XmlElement (name = "lower")
    private int lower;

    @XmlElement (name = "higher")
    private int higher;

    .
    .
    ???
}


然后像这样阅读它:


And then read it like this:

@POST
@PATH(<somePath>)
@Consumes(MediaType.APPLICATION_XML)
@Produces(MediaType.TEXT_PLAIN)
public String myFun(RangeClass range) {
  .
  .
  .
}


我所缺少的(如果其他部分正确的话)是如何定义我在元素内部具有属性.如果我添加"@XmlAttribute"注释,则该注释将引用根元素的属性(范围"),而不是特定元素的属性(较低"或较高").


The thing that i am missing (if the other parts are correct) is how to define that i have attributes inside the elements. If i put an '@XmlAttribute' annotation this will refer to an attribute of the root element ('range') and not an attribute of a specific element ('lower' or 'higher').

推荐答案

首先,最简单的方法是为每个XML标签创建一个Java映射:

First and the easiest way is to create a Java mapping per each XML tag:

@XmlRootElement(name = "range")
public class RangeClass {

    private Higher higher;

    private Lower lower;
}

@XmlElement(name = "higher")
public class Higher {

    @XmlAttribute
    private int value;
}

@XmlElement(name = "lower")
public class Lower {

    @XmlAttribute
    private int value;
}

第二选项是将XML结构更改为:

Second option is to change XML structure to:

<range>
  <higher>3</higher>
  <lower>2</lower>
</range>

然后您可以使用 @XmlElement 批注:

@XmlRootElement(name = "range")
@XmlAccessorType(XmlAccessType.FIELD) 
public class RangeClass {

    @XmlElement
    private int lower;

    @XmlElement
    private int higher;

}

第三选项是使用 Eclipse链接Moxy 和其@XmlPath批注:

Third option is to use Eclipse Link Moxy and its @XmlPath annotation:

@XmlRootElement(name = "range")
@XmlAccessorType(XmlAccessType.FIELD) 
public class RangeClass {

    @XmlPath("lower/@value")
    private int lower;

    @XmlPath("higher/@value")
    private int higher;

}

这篇关于REST:将通过POST传递的XML内容转换为Java对象,该元素内部的属性的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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