Jmeter Groovy我如何用{替换此字符串 [英] Jmeter Groovy how can I replace this string with {

问题描述

在使用JSR223 Groovy的Jmeter中..我花了很多时间尝试在JSON块中替换此字符串

In Jmeter with JSR223 Groovy .. I have spent a lot of time trying to replace this string in a JSON block

"ABC": {"seconds": 20}, 

使用

"ABC": {"seconds": ${myVal}}, (this way my value in seconds is variable)

我尝试过

str1 = str1.replaceAll('"ABC": {"seconds": 20}', '"ABC": {"seconds": '+${myVal}+'"}"');

但是它行不通.请帮助

推荐答案

使用正则表达式替换JSON中的值不是最好的主意，因为它非常脆弱，任何多余的空格或换行符都会破坏您的测试.

Replacing values in JSON using regular expressions is not the best idea as it will be very fragile and any extra space or line break will ruin your test.

我建议您使用 JsonSlurper 和 JsonBuilder 类组合代替.此外，不要将JMeter变量称为${myVal}，更好的选择是vars.get('myVal').

I would recommend going for JsonSlurper and JsonBuilder classes combination instead. Moreover, don't refer JMeter Variables as ${myVal}, a way better option would be vars.get('myVal').

完整的示例代码，以防万一:

Full example code just in case:

vars.put('myVal', '1234')

def foo = '{\n' +
        '  "ABC": {\n' +
        '    "seconds": 20\n' +
        '  }\n' +
        '}'

def json = new groovy.json.JsonSlurper().parseText(foo)
json.ABC.seconds = vars.get('myVal') as int
log.info(new groovy.json.JsonBuilder(json).toPrettyString())

演示:

更多信息:

• Groovy:解析和生成JSON
• Apache Groovy-为什么和如何使用它

• Groovy: Parsing and Producing JSON
• Apache Groovy - Why and How You Should Use It

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