连接两个选择语句 [英] joining two select statements
问题描述
谁能告诉我以下原因为什么不起作用?它抱怨两个选择之间的连接关键字附近存在语法错误.
Can anyone tell me why the following won't work? It complains of a syntax error near the join key word between the two selects.
SELECT *
FROM ( select * from orders_products inner JOIN orders ON orders_products.orders_id = orders.orders_id where products_id = 181)
as A
join
SELECT *
FROM ( select * from orders_products INNER JOIN orders ON orders_products.orders_id = orders.orders_id where products_id = 180)
as B
on A.orders_id=B.orders_id
基本上,我的第一个SELECT
从一个表中提取某个产品的所有订单信息,并从另一个表中提取订购数量,并将它们连接在一起.第二个SELECT
对另一种产品执行相同的操作.
Basically my first SELECT
pulls all the order info for a certain product from one table and pulls the quantity ordered from another and joins them together. The second SELECT
does the same thing for another product.
现在,我有
_______A_________ _______B_________
O_ID P_ID Q O_ID P_ID Q
1 180 3 1 181 11
2 180 9 2 181 6
3 180 5 3 181 3
然后,我想使用另一个联接
And, using another join I want to get
Q_ID P_ID1 Q1 P_ID2 Q2
1 180 3 181 11
2 180 9 181 6
3 180 5 181 3
也许我在这里采用了错误的方法.有什么建议吗?
Maybe I am taking a wrong approach here. Any suggestions?
更新: 这是RedFilter指针之后对我有用的东西:
UPDATE: Here is what worked for me after pointers by RedFilter:
(SELECT *
FROM (
SELECT * FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id =181) AS A
LEFT JOIN (
SELECT * FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id =180) AS B ON A.orders_id = B.orders_id
)
UNION (
SELECT *
FROM (
SELECT *
FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id =181
) AS C
RIGHT JOIN (
SELECT *
FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id =180
) AS D ON C.orders_id = D.orders_id
)
推荐答案
不确定要执行的操作,但是有两个select子句.改为执行此操作:
Not sure what you are trying to do, but you have two select clauses. Do this instead:
SELECT *
FROM ( SELECT *
FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id = 181) AS A
JOIN ( SELECT *
FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id = 180) AS B
ON A.orders_id=B.orders_id
更新:
您可能可以将其简化为以下形式:
You could probably reduce it to something like this:
SELECT o.orders_id,
op1.products_id,
op1.quantity,
op2.products_id,
op2.quantity
FROM orders o
INNER JOIN orders_products op1 on o.orders_id = op1.orders_id
INNER JOIN orders_products op2 on o.orders_id = op2.orders_id
WHERE op1.products_id = 180
AND op2.products_id = 181
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