合并两个选择语句以进行日期比较 [英] Combine two select statements for date comparison
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问题描述
我有以下陈述:
DECLARE @currentWEEK INT
DECLARE @previousWEEK INT
DECLARE @CURRENDATE DATETIME
DECLARE @PREVIOUSDATE DATETIME
SET @PREVIOUSDATE = YEAR(DATEADD(YEAR, -1, GETDATE()))
SET @CURRENDATE = GETDATE()
SET @currentWEEK = RIGHT(DATENAME(wk,'2013-05-17 00:00:00.000'),2)
SET @previousWEEK = RIGHT(DATENAME(wk,'2012-05-17 00:00:00.000'),2)
SELECT COUNT(*)
FROM vevents
WHERE RIGHT(DATENAME(wk,dbo.vEvents.DateCreated),2) = @currentWEEK
AND
YEAR(dbo.vEvents.DateCreated) = YEAR(@CURRENDATE)
SELECT COUNT(*)
FROM vevents
WHERE RIGHT(DATENAME(wk,dbo.vEvents.DateCreated),2) = @previousWEEK
AND
YEAR(dbo.vEvents.DateCreated) = @PREVIOUSDATE
本质上,它比较给定一周内两个日期的总计,但是我想结合给定日期的两个选择语句以返回单个记录集(例如CURRENTYEARCOUNT和PREVIOUSYEARCOUNT)
Essentially it compares a total for two dates within a given week, but I would like to combine the two select statements for given dates to return a single record set(eg CURRENTYEARCOUNT AND PREVIOUSYEARCOUNT)
非常感谢您的帮助
推荐答案
尝试一下-
DECLARE
@currentWEEK INT
, @previousWEEK INT
, @CURRENDATE DATETIME
, @PREVIOUSDATE DATETIME
SELECT
@PREVIOUSDATE = YEAR(DATEADD(YEAR, -1, GETDATE()))
, @CURRENDATE = GETDATE()
, @currentWEEK = RIGHT(DATENAME(wk, '20130517'), 2)
, @previousWEEK = RIGHT(DATENAME(wk, '20120517'), 2)
SELECT
COUNT(CASE WHEN YEAR(e.DateCreated) = @PREVIOUSDATE THEN 1 END)
, COUNT(CASE WHEN YEAR(e.DateCreated) = YEAR(@CURRENDATE) THEN 1 END)
FROM dbo.vEvents e
WHERE RIGHT(DATENAME(wk, e.DateCreated), 2) = @currentWEEK
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