从其他表连接最大值的最佳和最佳方法 [英] Best and optimal way to join max value from other table
问题描述
我想找到运行此查询的最佳方法,这里是细节,可以说以下是我的表及其数据:
I want to find the optimal way to run this query, here the details, lets say the following are my tables with their data:
-- User Table
DROP TABLE IF EXISTS `users`;
CREATE TABLE `users` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(30) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM;
-- Entries
INSERT INTO `users` VALUES (1,'user_a');
INSERT INTO `users` VALUES (2,'user_b');
INSERT INTO `users` VALUES (3,'user_c');
-- User Log Table
DROP TABLE IF EXISTS `user_log`;
CREATE TABLE `user_log` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`idrel` int(11) NOT NULL,
`event` varchar(20) NOT NULL,
`log` datetime NOT NULL,
PRIMARY KEY (`id`),
KEY `idrel` (`idrel`,`log`)
) ENGINE=MyISAM;
-- Entries
INSERT INTO `user_log` VALUES (1,1,'log1','2014-01-01 13:00:00');
INSERT INTO `user_log` VALUES (2,1,'log2','2014-01-02 13:00:00');
INSERT INTO `user_log` VALUES (3,2,'log3','2014-01-03 13:00:00');
INSERT INTO `user_log` VALUES (4,2,'log4','2014-01-04 13:00:00');
INSERT INTO `user_log` VALUES (5,3,'log5','2014-01-05 13:00:00');
INSERT INTO `user_log` VALUES (6,3,'log6','2014-01-06 13:00:00');
我想查询参加最近记录的事件的用户,我找到了两种方法来执行此操作,但是我不知道哪种方法最好(谈论两个表增长时的速度)或是否还有另一种方法,这是我的查询:
And I want to query the users joining the latest event logged, I have found two ways to do this but I don't know which one is the best (talking about speed when both tables grow) or if there is another way, here are my queries:
-- Query 1
SELECT
u.id,
u.name,
l2.event as last_record
FROM
users AS u
INNER JOIN
(
SELECT
idrel,
MAX(id) as last_id
FROM user_log
GROUP BY
idrel
) AS l1
ON (l1.idrel = u.id)
INNER JOIN
user_log AS l2
ON (l2.id = l1.last_id);
哪个给我这个结果:
+----+--------+-------------+
| id | name | last_record |
+----+--------+-------------+
| 1 | user_a | log2 |
| 2 | user_b | log4 |
| 3 | user_c | log6 |
+----+--------+-------------+
3 rows in set (0.00 sec)
-- Query 2
SELECT
u.id,
u.name,
(
SELECT event FROM user_log WHERE idrel = u.id ORDER BY log DESC LIMIT 1
) AS last_record
FROM
users AS u;
结果:
+----+--------+-------------+
| id | name | last_record |
+----+--------+-------------+
| 1 | user_a | log2 |
| 2 | user_b | log4 |
| 3 | user_c | log6 |
+----+--------+-------------+
3 rows in set (0.00 sec)
哪个是最好的方法?还有其他更好的方法吗?
Which one could be the best way? Is there any other better way?
推荐答案
不要那样做,这是一种更好的方法,首先,添加一个字段,将任何新日志条目的最后一个ID存储在users表上,然后创建一个触发器,以在插入的每个新字段上更新该字段,然后(可选)创建一个视图,以获取要查询的完整表".
Don’t do it that way, here is a better way, first, add a field to store on the users table the last ID of any new log entry, then create a trigger that updates that field on each new field inserted, then (optional) create a view to have a complete "table" to query from.
-- Add new field to save the modified id
ALTER TABLE `users` ADD `last_mod_id` INT(11) NOT NULL, ADD INDEX (`last_mod_id`);
-- Drop the trigger just in case it exists
DROP TRIGGER IF EXISTS `update_last_id`;
-- Create a trigger to save the last modified id each time a row is created
DELIMITER ;;
CREATE TRIGGER update_last_id
AFTER INSERT ON user_log
FOR EACH ROW
BEGIN
UPDATE `users`
SET `last_mod_id` = NEW.id
WHERE `id` = NEW.idrel;
END;
;;
-- Emtpy your table
TRUNCATE `user_log`;
-- Create all new registries
INSERT INTO `user_log` VALUES (1,1,'log1','2014-01-01 13:00:00');
INSERT INTO `user_log` VALUES (2,1,'log2','2014-01-02 13:00:00');
INSERT INTO `user_log` VALUES (3,2,'log3','2014-01-03 13:00:00');
INSERT INTO `user_log` VALUES (4,2,'log4','2014-01-04 13:00:00');
INSERT INTO `user_log` VALUES (5,3,'log5','2014-01-05 13:00:00');
INSERT INTO `user_log` VALUES (6,3,'log6','2014-01-06 13:00:00');
-- Query
SELECT
u.id,
u.name,
u.last_mod_id,
l.event,
l.log
FROM
`users` as u
INNER JOIN
`user_log` as l
ON (l.id = u.last_mod_id)
-- Drop view if exists
DROP VIEW IF EXISTS `users_log_view`;
-- View
CREATE VIEW `users_log_view` AS
SELECT
u.id,
u.name,
u.last_mod_id,
l.event,
l.log
FROM
`users` as u
INNER JOIN
`user_log` as l
ON (l.id = u.last_mod_id);
-- Query
SELECT * FROM `users_log_view` WHERE `id` = 1;
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