如何使用JPA保留LocalDate? [英] How to persist LocalDate with JPA?
问题描述
我想将没有时间的日期存储到我的数据库中.所以我选择使用LocalDate
类型.
I want to store date without time into my database. So I choose to use LocalDate
type.
如此处所述 https://thoughts-on-java.org /persist-localdate-localdatetime-jpa/我使用转换器将LocalDate
转换为Date
.
As mentionned here https://thoughts-on-java.org/persist-localdate-localdatetime-jpa/ I use a converter to convert LocalDate
to Date
.
但是,当我要保留我的实体(带有POST和PUT请求)时,会遇到一些麻烦.
However, I have some troubles when I want to persist my entity (with POST and PUT requests).
错误
2019-02-23 11:26:30.254 WARN 2720 --- [-auto-1-exec-10] .w.s.m.s.DefaultHandlerExceptionResolver : Resolved [org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Expected array or string.; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Expected array or string.
at [Source: (PushbackInputStream); line: 1, column: 104] (through reference chain: ...entity.MyObject["startdate"])]
org.springframework.http.converter.HttpMessageConversionException: Type definition error: [simple type, class org.springframework.http.ResponseEntity]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `org.springframework.http.ResponseEntity` (no Creators, like default construct, exist): cannot deserialize from Object value (no delegate- or property-based Creator)
at [Source: (PushbackInputStream); line: 1, column: 2]
代码
转换器
package ...entity;
import javax.persistence.AttributeConverter;
import javax.persistence.Converter;
import java.time.LocalDate;
import java.sql.Date;
@Converter(autoApply = true)
public class LocalDateAttributeConverter implements AttributeConverter<LocalDate, Date> {
@Override
public Date convertToDatabaseColumn(LocalDate locDate) {
return (locDate == null ? null : Date.valueOf(locDate));
}
@Override
public LocalDate convertToEntityAttribute(Date sqlDate) {
return (sqlDate == null ? null : sqlDate.toLocalDate());
}
}
实体
package ...entity;
import org.hibernate.annotations.ColumnDefault;
import javax.persistence.*;
import java.time.LocalDate;
import java.util.HashSet;
import java.util.Set;
@Entity
public class MyObject {
@Id
private String id;
private LocalDate startdate;
private LocalDate enddate;
public MyObject() {}
public MyObject(LocalDate enddate) {
this.startdate = LocalDate.now();
this.enddate = enddate;
}
...
}
主要"
private DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
MyObject myobject = new MyObject(LocalDate.parse("2019-03-01", formatter));
感谢您的帮助.
打印MyObject
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<String> entity = new HttpEntity<>(this.toJsonString(myObject), headers);
System.out.println(entity.toString());
// <{"id":"ba6649e4-6e65-4f54-8f1a-f8fc7143b05a","startdate":{"year":2019,"month":"FEBRUARY","dayOfMonth":23,"dayOfWeek":"SATURDAY","era":"CE","dayOfYear":54,"leapYear":false,"monthValue":2,"chronology":{"id":"ISO","calendarType":"iso8601"}},"enddate":{"year":2019,"month":"MARCH","dayOfMonth":1,"dayOfWeek":"FRIDAY","era":"CE","dayOfYear":60,"leapYear":false,"monthValue":3,"chronology":{"id":"ISO","calendarType":"iso8601"}}},[Content-Type:"application/json"]>
推荐答案
使用JPA 2.2,无需任何转换器. Hibernate从5.3版本开始支持它. https://vladmihalcea. com/whats-new-in-jpa-2-2-java-8-date-and-time-types/
Using JPA 2.2 no converter is needed. Hibernate supports it as of 5.3 version. https://vladmihalcea.com/whats-new-in-jpa-2-2-java-8-date-and-time-types/
这篇关于如何使用JPA保留LocalDate?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!