获取使用android系统中asmack错误请求400错误 [英] Getting bad request 400 error using asmack in android

问题描述

我试图使用登记我的XMPP客户端使用asmack库中的Andr​​oid ejabberd服务器上的新用户。问题是，我收到以下错误：放大器;是不是在服务器上创建的用户：

 坏请求（400）
在org.jivesoftware.smack.AccountManager.createAccount（AccountManager.java:243）
在in.ui.MainActivity $ 1 $ 1 $ 1.run（MainActivity.java:316）
在java.lang.Thread.run（Thread.java:841）
 

以下是code：

  _xmppUsername = XMPPConfig.getStringUserInfoValue（XMPPConfig.XMPP_CLIENT_ID）;
_xmppPassword = XMPPConfig.getStringUserInfoValue（XMPPConfig.XMPP_CLIENT_PASSWORD）;
_xmppHost = XMPPConfig.getStringUserInfoValue（XMPPConfig.XMPP_HOST）;
尝试{
    _xmppPortNo =的Integer.parseInt（XMPPConfig.getStringUserInfoValue（XMPPConfig.XMPP_PORT））;
}赶上（例外五）{
    e.printStackTrace（）;
    Log.e（TAG，e.getMessage（））;
}
_xmppServiceName = XMPPConfig.getStringUserInfoValue（XMPPConfig.XMPP_SERVICE_NAME）;ConnectionConfiguration conconfig的=新ConnectionConfiguration（_xmppHost，_xmppPortNo，_xmppServiceName）;_xmppConnection =新XMPPConnection（安装了conconfig）;如果（！_xmppConnection.isAuthenticated（））{
    登录 （）;
}
/ *
 *如果连接没有建立或已建立与放大器;
 *再破请登录
 * /    @覆盖
    公共无效昂秀（最终DialogInterface对话）{
        按钮positiveButton = _dlgRegistration.getButton（DialogInterface.BUTTON_POSITIVE）;
        positiveButton.setOnClickListener（新View.OnClickListener（）{
            @覆盖
            公共无效的onClick（视图v）{                //创建线程注册
                新主题（新的Runnable接口（）{
                    @覆盖
                    公共无效的run（）{
                        字符串clientID的= NULL;
                        字符串密码= NULL;                            clientID的=用户+ XMPP_SERVICE_NAME;
                            尝试{                                //充分利用UUID的哈希密码
                                密码=密码;
                                Log.i（TAG，clientID的+密码）;
                            }赶上（抛出：NoSuchAlgorithmException E1）{
                                e1.printStackTrace（）;
                            }赶上（UnsupportedEncodingException E1）{
                                e1.printStackTrace（）;
                            }
                        }
                        的AccountManager经理= _xmppConnection.getAccountManager（）;
                        尝试{
                                //在服务器上创建账户
                                manager.createAccount（客户端ID，密码，attr）使用;                                                            }
                        }赶上（XMPPException E）{
                            e.printStackTrace（）;
                        }
                    }
                }）开始（）;
            }
        }）;
 

解决方案

但问题是这一行 clientID的=用户+ XMPP_SERVICE_NAME; 其中，我不应该被之后追加域或服务名称用户。

I am trying to register a new user using my XMPP client using asmack library in Android on ejabberd server. The problem is that I am getting following error & the user is not being created on the server:

bad-request(400)
at org.jivesoftware.smack.AccountManager.createAccount(AccountManager.java:243)
at in.ui.MainActivity$1$1$1.run(MainActivity.java:316)
at java.lang.Thread.run(Thread.java:841)

Following is the code:

_xmppUsername = XMPPConfig.getStringUserInfoValue (XMPPConfig.XMPP_CLIENT_ID);
_xmppPassword = XMPPConfig.getStringUserInfoValue (XMPPConfig.XMPP_CLIENT_PASSWORD);
_xmppHost = XMPPConfig.getStringUserInfoValue (XMPPConfig.XMPP_HOST);
try {
    _xmppPortNo = Integer.parseInt (XMPPConfig.getStringUserInfoValue (XMPPConfig.XMPP_PORT));
} catch (Exception e) {
    e.printStackTrace ();
    Log.e (TAG, e.getMessage ());
}
_xmppServiceName = XMPPConfig.getStringUserInfoValue (XMPPConfig.XMPP_SERVICE_NAME);

ConnectionConfiguration conConfig = new ConnectionConfiguration (_xmppHost, _xmppPortNo, _xmppServiceName);

_xmppConnection = new XMPPConnection (conConfig);

if (!_xmppConnection.isAuthenticated ()) {
    login ();
}
/*
 * If connection has not been established or had been established &
 * broken again then login
 */

    @Override
    public void onShow (final DialogInterface dialog) {
        Button positiveButton = _dlgRegistration.getButton (DialogInterface.BUTTON_POSITIVE);
        positiveButton.setOnClickListener (new View.OnClickListener () {
            @Override
            public void onClick (View v) {

                // Creating registration thread
                new Thread (new Runnable () {
                    @Override
                    public void run () {
                        String clientID = null;
                        String password = null;

                            clientID = "user" + XMPP_SERVICE_NAME;
                            try {

                                // Getting hash password from UUID
                                password = "password";
                                Log.i (TAG, clientID + password);
                            } catch (NoSuchAlgorithmException e1) {
                                e1.printStackTrace ();
                            } catch (UnsupportedEncodingException e1) {
                                e1.printStackTrace ();
                            }
                        }
                        AccountManager manager = _xmppConnection.getAccountManager ();
                        try {


                                // Creating account on the server
                                manager.createAccount (clientID, password, attr);

                                                            }
                        } catch (XMPPException e) {
                            e.printStackTrace ();
                        }
                    }
                }).start ();
            }
        });

解决方案

The problem was this line clientID = "user" + XMPP_SERVICE_NAME; where I shouldn't have been appending Domain or Service Name after "user".

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