解析Unix时间到Java在Android [英] parsing Unix time to java on android

问题描述

美好的一天。我工作的小程序，目前我正在试图解析来自JSON对象（在CouchDB的）一个Unix时间。我曾尝试多种方法，但是这一个我认为最接近。现在，我得到NumberFormatException异常：长期无效时间误差

Good day. I'm working on little application and currently I'm trying to parse a Unix time from JSON object (on CouchDB). I have tried several ways, but this one I think is closest. Now I get NumberFormatException: Invalid long: "Time" error

private Points parseJsonDocument(JSONObject json) throws JSONException, ParseException
{

    String openKey = JSON_MAP.get(MAP_OPEN);
    String closeKey = JSON_MAP.get(MAP_CLOSE);
    String highKey = JSON_MAP.get(MAP_HIGH);
    String lowKey = JSON_MAP.get(MAP_LOW);
    String volumeKey = JSON_MAP.get(MAP_VOLUME);
    String dateKey = JSON_MAP.get(MAP_DATE);


    JSONObject object = json.getJSONObject("Stock");
    JSONArray array = object.getJSONArray("Data");
//  JSONArray array = json.getJSONArray("Data");
    Points result = new Points();


    SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); //desired format

    Long time = Long.parseLong(dateKey);
    final Calendar cal = Calendar.getInstance();
    cal.setTimeInMillis(time *1000);



    for(int i=0;i<array.length();i++)
    {
        JSONObject obj = array.getJSONObject(i);

        Point cp = new Point();
        cp.c = obj.getDouble(closeKey);
        cp.h = obj.getDouble(highKey);
        cp.l = obj.getDouble(lowKey);
        cp.o = obj.getDouble(openKey);
        cp.v = obj.getDouble(volumeKey);

        String date = obj.getString(dateKey);
        cp.dt = df.parse(df.format(cal.getTime()));

        result.add(cp);
    }

    return result;
}

和JSON对象看起来是这样的：

and JSON object looks like this:

     {
   "_id": "abbv",
   "_rev": "12-3d250de8395a12e0c92dfb9d7d379fc4",
    "Stock": {
       "Data": [
       {
           "Time": "1386598949000",
           "Open": "50.17",
           "High": "0",
           "Low": "0",
           "Close": "51.37",
           "Volume": "7285755"
       }
]
}

这可能是一些愚蠢的错误，我只是不明白，因为缺乏经验，所以任何建议或指导将AP preciated。是的，我曾尝试阅读的javadoc，但我便无法找到解决方案。
谢谢你。

It's probably some silly mistake which I just don't see because of lack of experience, so any advice or guidance will be appreciated. And yes,I have tried reading javadocs but I could't find the solution. Thanks.

推荐答案

行长时间=的Long.parseLong（da​​teKey）;

正试图解析字符串的时间的一个龙。
<击>
我想你想要做的这是什么

is trying to parse the String Time as a Long. I think what you want to do is this

String timeString = array.getJSONObject(0).getString(dateKey);
Long time = Long.parseLong(timeString)

编辑：重新阅读你的code，我认为这个问题是你想太早解析您的日期

re-reading your code, I think the issue is you are trying to parse your date too early.

您需要招行长时间=的Long.parseLong（da​​teKey）; 下来到您的JSON解析循环

you need to move the line Long time = Long.parseLong(dateKey); down into your JSON parsing loop.

然后，而不是长时间=的Long.parseLong（da​​teKey）; ，你应该分析，而不是日期的日期的值 < STRONG>键，所以的Long.parseLong（日期）;

then, instead of Long time = Long.parseLong(dateKey);, you should parse the date value as opposed to the date key, so Long.parseLong(date);

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