将值传递给jquery对话框形式 [英] pass value to jquery dialog form
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问题描述
我需要一个对话框窗口来弹出表单并将值传递给该表单.我已经尝试了几种方法来解决此问题,但我一直无法这样做.我到处搜寻,似乎没有任何作用.
I need a dialog window to popup with a form and pass a value to this form. I have attempted several approaches to this problem but I have been unable to do so. I have searched all over and nothing seems to work.
这是我最近的尝试:
var message="variable";
.click(function() {
$( "#dialog-form" ).dialog( "open" );
$('<input>').attr({
type: 'text',
id: 'hidden-input",
value: message,
name: 'bar'
}).appendTo("#dialog-form");
如果我将追加内容放入对话框中,弹出窗口将停止工作(我认为我不知道如何正确执行此操作)
If i put the append inside the dialog the popup stops working (i think i dont know how to do this properly)
推荐答案
我认为您正在寻找这样的东西:
I think you're looking for something like this:
<script>
$(function(){
var message = "variable";
$("#showDialog").click(function() {
$("#hidden-input").val(message);
$("#dialogForm").dialog("open");
});
});
</script>
<button id="showDialog">Show Dialog</button>
<div id="dialogForm">
<input type="text" id="hidden-input" name="bar"/>
</div>
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