将ID传递给jquery模态形式 [英] pass id to jquery modal form

问题描述

我有下表，其中我显示数据库中的数据.当我单击编辑"按钮时，将出现一个对话框，我需要在数据库的文本框中显示数据.但是要从db获取数据，我需要模式中的player_id.

i have following table where i am showing data from database. when i click edit button a dialog appear, there i need to show data in text boxes from db. but for getting data from db i need player_id in modal from.

<td><?php echo $player_id ?></td>
<td><?php echo $name; ?></td>
<td><?php echo $details; ?></td>
<td><button id="update_user">Edit</button></td>

所以在这里我想将player_id传递给jquery模态形式，在那里我可以基于该特定播放器的player_id从db获取数据，并在文本框中显示，然后再次更新为db.

so here i want to pass player_id to jquery modal form, where i can get data from db on the base of player_id for that specific player and show in text boxes and then again update to db.

<div id="update-form" title="Update Employee">

    <label for="id">ID</label>
    <input type="text" name="player_id" id="player_id" value="$player_id" />
    <label for="name">Name</label>
    <input type="text" name="name" id="name" value="$name"/>
          <label for="details">Details</label>
    <input type="text" name="details" id="details" value="$details"/>

我想将$ player_id变量传递给jquery模态形式.就是这样.

i want to pass $player_id variable to jquery Modal form. that's all.

推荐答案

尝试如下操作:

<td><?php echo $player_id ?></td>
<td><?php echo $name; ?></td>
<td><?php echo $details; ?></td>
<td>
    <button class="update_user" data-payer_id="<?php echo $player_id ?>">Edit</button>
</td>

<script>
$(".update_user").click(function(){
    var player_id = $(this).attr('data-payer_id');
    $("#update-form").find("#player_id").val(player_id);
    $("#update-form").dialog("open");
});
</script>

PS:player_id应该是对话框表单中的隐藏字段，除非它是可编辑的.

PS: player_id should be a hidden field in the dialog form unless it is editable.

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