删除索引处的单个孩子 [英] Remove single child at index

问题描述

有一些示例可在给定索引后分离所有子级(例如此一)，但不能仅删除其中一项.

There's examples to detach all children after a given index (like this one), but nothing to just remove one.

我尝试过的事情(显然是错误的):

Things I have tried (which are obviously incorrect):

this.element.find('.nav-tabs').children().splice(index, 1).remove();
this.element.find('.nav-tabs').children().slice(index).detach();

以及其他一些变化.我需要类似第二个选项的内容，该选项还可以保留该索引之后的子级.我想念什么?我可以拼接一下，然后以某种方式重新分配孩子吗?

and some other variations on that. I need something like the second option that preserves the children after that index as well. What am I missing? Can I splice it and reassign the children somehow?

推荐答案

您可以使用eq()通过其索引将集合中的元素作为目标.试试这个:

You can use eq() to target an element in a collection by its index. Try this:

this.element.find('.nav-tabs').children().eq(index).remove();

> 小提琴示例

splice()和slice()对您不起作用的原因是因为它们返回DOMElements数组，而不是jQuery对象.

The reason splice() and slice() don't work for you is because they return an array of DOMElements, not a jQuery object.

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