从 redis 列表中删除特定索引处的元素 [英] Remove element at specific index from redis list

问题描述

是否可以删除 redis 列表中特定索引处的元素?没有真正找到我想要的.修剪允许您选择一组特定的元素，LREM 允许您按值删除列表中的项目，但我没有该值.

Is it possible to remove an element at a specific index in an redis list ? Not really finding what I want. There is trim which allows you to select an specific set of elements, LREM allows you to delete an item in a list by value, but I dont have the value.

我发现了一个技巧，您可以使用 LSET 将元素的值更改为 UID 或字符串，例如'DELETED'，然后你在这个值上调用 LREM.不过这感觉有点脏.

I found an hack where you use LSET to change the value of the element to a UID or string e.g. 'DELETED', and the you call LREM on this value. This just feels a bit dirty though.

推荐答案

因此，实现我想要的唯一方法是将索引处的值设置为预先确定的字符串，然后按值进行删除.

So the only way to accomplish what I wanted was to set the value at the index to a pre determined string and then do an removal by value.

请参阅此处的讨论 https://groups.google.com/forum/#!topic/redis-db/c-IpJ0YWa9I

在ruby中如下

@redis.lset("#{@namespace}/#{specified_queue}", index, "DELETED")
@redis.lrem("#{@namespace}/#{specified_queue}", 1, "DELETED")

LSET 文档 http://redis.io/commands/lsetLREM 文档 http://redis.io/commands/lrem

LSET docs http://redis.io/commands/lset LREM docs http://redis.io/commands/lrem

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