在特定索引之后从列表中删除所有元素 [英] Remove all elements from a List after a particular index

问题描述

List / ArrayList中是否有任何方便的方法可以在特定索引之后删除List的所有元素。而不是手动循环通过它来移除。

Is there any convenient way in List/ArrayList by which we can remove all elements of a List after a particular index. Instead of manually looping through it for removing.

为了更加解释，如果我有10个元素的列表，我想提到索引3然后索引后的所有元素3被删除，我的列表现在只包含4个元素（从0开始计算）

To be more explanatory, if I have a list of 10 elements, I want to mention index 3 and then all elements after index 3 gets removed and my list would consist of only starting 4 elements now (counts from 0)

推荐答案

list.subList(4, list.size()).clear();

子列表操作反映在原始列表中，因此清除了从索引4到列表的所有内容。 size（） exclusive，又名索引后的所有内容3.范围删除专门用作文档中的示例：

Sublist operations are reflected in the original list, so this clears everything from index 4 inclusive to list.size() exclusive, a.k.a. everything after index 3. Range removal is specifically used as an example in the documentation:

此方法消除了对显式范围操作的需要（对于数组通常存在的
排序）。任何期望
列表的操作都可以通过传递子列表视图
而不是整个列表来用作范围操作。例如，以下习语从列表中删除
元素范围：

This method eliminates the need for explicit range operations (of the sort that commonly exist for arrays). Any operation that expects a list can be used as a range operation by passing a subList view instead of a whole list. For example, the following idiom removes a range of elements from a list:

     list.subList(from, to).clear();

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