Android中如何序列化XML？ [英] How can Serialize XML in Android?

问题描述

我得到在 XML 格式的肥皂 Serivce文字，现在我想分割图像标记，并在不同的序列化格式的视频标签。

我的文字：

 ＆LT;图像及GT;
＆lt;图像ImageID =1000032StoredFilename =42825125-8002-4d28-ba90-9889de5e4e91.jpgImageName =bPanda/＆GT;＆LT; /图片＆GT;
＆LT;播放列表和GT;＆LT;播放列表PlayListID =1000005/＆GT;
＆LT; /播放列表和GT;＆LT; PlayListVideoXrefs＆GT;
＆所述; PlayListVideoXref PlayListVideoXrefID =1000027PlayListID =1000005视频ID =1000006PlayOrder =1/＆GT;
＆所述; PlayListVideoXref PlayListVideoXrefID =1000028PlayListID =1000005视频ID =1000003PlayOrder =2/＆GT;
＆LT; / PlayListVideoXrefs＆GT;＆LT;影片及GT;
＆lt;视频视频ID =1000006StoredFilename =c0739234-b844-46c9-b1b2-96b55f70e17e.mp4VideoName =巴塞罗那/＆GT;
＆lt;视频视频ID =1000003StoredFilename =50acb2ee-810A-4c32-b097-40c87d253e25.mp4VideoName =bVideo1/＆GT;
＆LT; /视频＆GT;
 

我分裂使用正则表达式的形象和它不工作：

 模式P = Pattern.compile（＆LT;图片[^＆GT;] *方式＆gt;（*）＆LT;？/图片＆GT;）;
匹配M = p.matcher（_strUrl）;
ArrayList的＆LT;串GT; list_Images =新的ArrayList＆LT;串GT;（）;尝试{
    而（m.find（））{
        的System.out.println（m.group（1））;
        list_Images.add（m.group（1））;    }
}赶上（例外五）{
    // TODO：处理异常
    Toast.makeText（getApplicationContext（），e.​​getMessage（）的toString（），1）。.show（）;
}
 

解决方案

要捕捉图片部分，那么你可能需要转义斜杠

（。*？）

＆LT;图片[^＆GT;] * GT＆LT; \\ /图片＆GT; ，活生生的例子： http://www.rubular.com/r/h5TZdE5nyb

要分析每个属性的单个图像标签：

\\ s（[^ =] *）=（[^] *），活生生的例子： http://www.rubular.com/r/eiTS7cpY5p

I'm getting a text in XML Format with Soap Serivce and now I want to split an Image tag and a Video Tag in different Serialize format.

My text :

<Images> 
<Image ImageID="1000032" StoredFilename="42825125-8002-4d28-ba90-9889de5e4e91.jpg" ImageName="bPanda"  /></Images>
<PlayLists><PlayList PlayListID="1000005"  />
</PlayLists><PlayListVideoXrefs>
<PlayListVideoXref PlayListVideoXrefID="1000027" PlayListID="1000005" VideoID="1000006" PlayOrder="1"  />
<PlayListVideoXref PlayListVideoXrefID="1000028" PlayListID="1000005" VideoID="1000003" PlayOrder="2"  />
</PlayListVideoXrefs>

<Videos>
<Video VideoID="1000006" StoredFilename="c0739234-b844-46c9-b1b2-96b55f70e17e.mp4" VideoName="barcelona"  />
<Video VideoID="1000003" StoredFilename="50acb2ee-810a-4c32-b097-40c87d253e25.mp4" VideoName="bVideo1"  />
</Videos>

I split the Image using Regex and it's not working at all :

Pattern p = Pattern.compile("<Images[^>]*>(.*?)</Images>");
Matcher m = p.matcher(_strUrl);
ArrayList<String> list_Images = new ArrayList<String>();

try {
    while (m.find()) {
        System.out.println(m.group(1));
        list_Images.add(m.group(1));

    }
} catch (Exception e) {
    // TODO: handle exception
    Toast.makeText(getApplicationContext(), e.getMessage().toString(), 1).show();
}

解决方案

To capture the images section then you'll probably need to escape the forward slash

<Images[^>]*>(.*?)<\/Images>, Live example: http://www.rubular.com/r/h5TZdE5nyb

To parse each of the attributes in a single image tag:

\s([^=]*)="([^"]*)", Live example: http://www.rubular.com/r/eiTS7cpY5p

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