Localstorage:计算使用stringify时键中有多少个值 [英] Localstorage: Count how many values in key when using stringify

问题描述

如何计算1个本地存储密钥中有多少个不同的值.

How can I count how many different values I have in 1 localstorage key.

例如:

这是我的本地存储空间:

This is my localstorage:

[{"id":"item-1","icon":"google.com"},{"id":"item-2","icon":"youtube.com"}]

在此示例中，我想要2个不同值的警报.所以基本上我想计算{} ..

For this example I'd like an alert of 2 different values. So basically I want to count the {}..

有可能吗?

推荐答案

localStorage是一个对象，因此仅localStorage.length即可提供条目数.

localStorage is an object, so just localStorage.length gives you the number of entries.

但是我想我可能会误会你.您是说您拥有一个键，而该键的值是一个JSON.stringify对象?如果是这样，您可以执行JSON.parse(localStorage.keyname).length来反序列化值并计算其中的数量.

However I think I might be misunderstanding you. Do you mean you have one key, and that key's value is a JSON.stringify'd object? If so, you could do JSON.parse(localStorage.keyname).length to unserialise the value and count how many there are in there.

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