絮状饼图不显示(修订后的代码) [英] Flot pie chart doesn't show (revised code)

问题描述

我需要一个饼图，并找到了 Flot .它看起来简单而强大，但是我发现的所有示例都使用固定值(例如[1,2])描述了数据"，但我需要显示动态数据.我有五个变量，这些变量最终必须加起来为100.我只想包括那些值> 0的变量，如果它们的总和不等于100，我想添加一个元素来显示缺失的百分比.问题是我不知道如何动态构造数据参数.

I need a pie chart and found Flot. It looks simple and powerful, but all of the examples I have found describe the "data" using fixed values (e.g. [1,2]) but I need to show dynamic data. I have five variables that must ultimately add up to 100. I want to include only those that have a value > 0, and if they don't total to 100, I want to add an element that shows the missing percent. The problem is that I don't know how to dynamically construct the data parameter.

我的代码如下.它有两个问题: 1)$ .plot什么都不做-没有错误也没有grapy 2)我不知道如何添加标签文字

My code is below. There are two problems with it: 1) The $.plot does nothing - no error and no grapy 2) I don't know how to add the label text

function updatePieChart() {
    var total = 0;
    var data = new Array();
    var verb = "";
    var dataIndex = 0;

    for (var dataIndex = 0; dataIndex < 5; dataIndex++) {
        var duty = "DUTY_" + (dataIndex + 1);
        var d = getData(duty + "_PERCENTAGETIMESPENT");
        if (isNumeric(d)) {
            d = parseInt(d);
            if (d > 0) {
                total += d;
                data[dataIndex] = new Array();
                data[dataIndex].push(d);
                verb = getData(duty + "_SKILL");
                if (verb == "") verb = duty + dataIndex;
                log(duty + dataIndex + ' value: ' + d);
            }
        }
    }

    var count = data.length;
    if (total != 100) {
        if (total < 100) {
            var missingDataNum = 100 - total;
            data[count] = new Array();
            data[count].push(missingDataNum);
            verb = '**MISSING**';
            log(verb + missingDataNum);
        }
    }

    $.plot($('#pieChart'), data,
        {
        series: {
            pie: {
                show: true,
            }
        },
        legend: {
            show: false
        }
    });
}

推荐答案

已修复.参见什么是将数据作为变量传入时jQuery Flot数据的格式.问题是我没有将数据对象正确格式化为jSON对象.

Fixed. See What is the format of jQuery Flot data when passing in the data as variables. Problem was that I wasn't formatting the data object as a jSON object correctly.

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