如何使用href调用函数? [英] How can I call a Function with a href?
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问题描述
我正在尝试将函数调用到href
中,我的function
在functions.php
上
而我的href
在views/something.php
I´m trying to call a function into a href
, my function
is on functions.php
and my href
is on views/something.php
所以,这是我的功能:
function discount($connection, $us){
$discount = $conexion->prepare("UPDATE postule SET seen = 1 WHERE id = $us");
$discount->execute();
return $discount;
}
而我的link button
在<li>
上(不是形式):
and my link button
is on an <li>
(not in a form):
<?php foreach ($total_notu as $notu) : ?>
<li><a onClick="<?php discount() ?>" href="notificaciones.php"> Notificaciones <span class="badge "><?php echo "$notu[0]"; ?></span></a></li>
<?php endforeach; ?>
(不要注意foreach)
(Do not pay attention to the foreach)
推荐答案
您需要将其更改为使用ajax调用或表单发布来调用PHP函数.
You'll need to change this to use an ajax call or form post to call the PHP function.
这是一个非常基本的示例,应该为您指明正确的方向
Here's a really basic example which should point you in the right direction
discount.php
discount.php
<?php
// Load $connection from somewhere
// Get user, it's better to get this from a cookie or session rather than GET
$user = $_GET['user']
$discount = $connection->prepare("UPDATE postule SET seen = 1 WHERE id = :user");
$discount->bindParam(':user', $user);
$result = $discount->execute();
// Throw error if something went wrong with the update, this will cause $.ajax to use the error function
if (!$result) {
http_response_code(500);
}
html,假设$notu[0]
包含用户ID
html, assuming $notu[0]
contains the user id
<?php foreach ($total_notu as $notu) : ?>
<li><a onClick="return callDiscount('<?php echo "$notu[0]"; ?>');" href="#"> Notificaciones <span class="badge "><?php echo "$notu[0]"; ?></span></a></li>
<?php endforeach; ?>
js,需要 jquery
function callDiscount(user_id)
{
// Perform ajax call to discount.php
$.ajax({
url: '/discount.php?user=' + user_id,
error: function() {
alert('An error occurred');
},
success: function(data) {
// Redirect user to notificaciones.php
document.location = '/notificaciones.php';
}
});
// Prevent link click doing anything
return false;
}
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