如何使用函数指针调用的函数？ [英] How to call the function using function pointer?

问题描述

假设我有三个功能：

bool A();
bool B();
bool C();

我如何调用这些函数有条件使用函数指针之一，我怎么声明函数指针？

How do I call one of these functions conditionally using a function pointer, and how do I declare the function pointer?

推荐答案

您可以执行以下操作：
假设你有你的A，B和; C函数如下：

You can do the following: Suppose you have your A,B & C function as the following:

bool A()
{
   .....
}

bool B()
{
   .....
}

bool C()
{

 .....
}

现在在一些其他的功能，比如在主要的：

Now at some other function, say at main:

int main()
{
  bool (*choice) ();

  // now if there is if-else statement for making "choice" to 
  // point at a particular function then proceed as following

  if ( x == 1 )
   choice = A;

  else if ( x == 2 )
   choice = B;


  else
   choice = C;

if(choice())
 printf("Success\n");

else
 printf("Failure\n");

.........
  .........
  }

记住，这是对函数指针的一个例子。还有其他一些方法，并为你必须清楚地了解函数指针。

Remember this is one example for function pointer. there are several other method and for which you have to learn function pointer clearly.

这篇关于如何使用函数指针调用的函数？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！