JSON解析与jQuery循环 [英] json parse with jQuery loop
问题描述
我的代码附在下面，尽管它是较大代码的一部分
hi my code is attached below, though its a part of bigger code
<html>
<head>
<style>
#results{margin-top:100px; width:600px; border:1px solid #000000; background-color:#CCCCCC; min-height:200px;}
</style>
<script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false"></script>
<script src="https://maps.googleapis.com/maps/api/js?sensor=false&libraries=places"></script>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
</head>
<body>
<div id="results"></div>
<script>
var input="Taj Mahal India";
var url = "http://maps.googleapis.com/maps/api/geocode/json?address=" + input + "&sensor=false";
var check = $.getJSON(url, function (data) {
console.log("inside getjson");
console.log(data);
$.each(data.results.address_components, function(i,inside){
if(inside.types[0]=="route"){
$("#results").append('<p> route : '+this.long_name +'</p>');
}
if(inside.types[0]=="locality"){
$("#results").append('<p> locality : '+this.long_name +'</p>');
}
if(inside.types[0]=="administrative_area_level_2"){
$("#results").append('<p> administrative area 2 : '+this.long_name +'</p>');
}
if(inside.types[0]=="administrative_area_level_1"){
$("#results").append('<p> administrative area 1 : '+this.long_name +'</p>');
}
if(inside.types[0]=="country"){
$("#results").append('<p> country : '+this.long_name +'</p>');
}
});
});
</script>
</body>
</html>
问题是它不起作用.我强烈怀疑我在$.each(data.results.address_components, function(i,inside)行中做错了什么.
The problem is that it doesn't work. I have a strong doubt that i have done something wrong in $.each(data.results.address_components, function(i,inside) line.
泰姬陵印度的JSON在这里 http://maps.googleapis.com/maps/api/geocode/json?address=Taj%20Mahal%20India&sensor=false
JSON for Taj Mahal India is here http://maps.googleapis.com/maps/api/geocode/json?address=Taj%20Mahal%20India&sensor=false
推荐答案
应为
$.each(data.results[0].address_components, function(i,inside)
代替
$.each(data.results.address_components, function(i,inside)
因为要从第一个results组中获取数据.这是 演示
because you are taking data from the first results set. Here is a demo
注意::我不知道是否可以有多个results.如果可以，那么您必须首先遍历results，然后在address_components上对其进行迭代.
Note: I don't know if there can be multiple results. If it can, then you must first iterate over the results and then inside it on address_components.
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