与.find()相反 [英] Opposite of .find()

问题描述

.find()是否相反?

Is there an opposite of .find()?

$('.myclass').except('#myid');

除了带有#myid的元素外，都将使用.myclass的所有元素. 我知道我可以在此示例中执行$('.myclass[id=myid]')，但在其他情况下似乎会有所帮助.

Would grab all elements with .myclass except the element with #myid. I know I could do $('.myclass[id=myid]') in this example, but seems like it would be helpful in other cases.

谢谢

感谢您的答复！好像我只是错过了在文档中看到.not()和:not()一样.

Thanks for the responses! Looks like I just missed seeing .not() and :not() in the documentation.

推荐答案

$('.myclass').not('#myid');

http://api.jquery.com/not/

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