与numpy.unwrap相反 [英] Opposite of numpy.unwrap

问题描述

在Python numpy中，有一个展开的功能:

In Python numpy, there is an unwrap function that:

通过改变绝对跳变大于不连续来解开弧度p 沿给定轴的2 * pi补码.

Unwrap radian phase p by changing absolute jumps greater than discont to their 2*pi complement along the given axis.

现在，我想执行相反的功能.如何包装一系列相位?例如.如何转换所有角度以将它们限制在-π和π之间?

Now, I'd like to do the opposite function. How can I wrap an array of phases? E.g. how to convert all angles to constraint them between -π and π?

显而易见的方法是执行以下操作:

The obvious way would be to do something like:

for i, a in enumerate(phases):
    while a < pi:
        a += 2 * pi
    while a > pi:
        a -= 2 * pi
    phases[i] = a

但是有一种更简单/更快的方法吗?

but is there a simpler / faster way?

推荐答案

phases = (phases + np.pi) % (2 * np.pi) - np.pi

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