创建一个调用jsf方法的简单链接 [英] creating a simple link that invokes a jsf method

问题描述

我正在建立注销链接，这是注销bean的代码.

i'm making a logout link and this is the code of the logout bean.

public void doLogout() {
    try {
        FacesContext.getCurrentInstance().getExternalContext().getSessionMap().put("user_info", null);
        FacesContext.getCurrentInstance().getExternalContext().redirect("../index.xhtml");
    } catch (Exception e) {
    }
}

在我的xhtml页面中

in my xhtml page i have

    <ul class="dropdown-menu">
        <li><h:outputLink value="#{logout.doLogout()}">Logout</h:outputLink></li>
    </ul>

我的问题是，当我进入该页面时，该页面会自动将我注销，并调用logout.doLogout()方法，而无需我单击链接本身.

my problem is when i get into the page, the page automatically logs me out, its invoking the logout.doLogout() method without me clicking the link itself.

我尝试擦除doLogout()中的代码，并将其更改为一个Sysout，然后调用该方法，而无需单击链接.

i tried erasing the code inside the doLogout() and just change it to simply a Sysout, and it does invoke the method with out me clicking the link.

推荐答案

对我来说太愚蠢了.<h:commandLink action="logout.doLogout()">Logout</h:commandLink>可以完成工作.

oh stupid of me.. <h:commandLink action="logout.doLogout()">Logout</h:commandLink> does the job.

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