如何在PHP中处理JSON? [英] How to process JSON in PHP?

问题描述

这是异步发送到我的php页面的JSON.本质上，这是一个产品列表，它将插入到我的mySQL数据库中.

Here is the JSON which is sent asynchronously to my php page. It is essentially a product list, which will be inserted into my mySQL database.

我的问题是用PHP解码JSON.我可以使用``eval''函数在js中做到这一点，但是在PHP中，我的努力导致了一系列复杂的爆炸和内爆函数.

My issue is decoding the JSON in PHP. I can do this fine in js with the 'eval' function, but in PHP my efforts have resulted in a complicated series of explode and implode functions.

{
    "Product": [
        {
            "Product_Title": "Cloth",
            "Product_Description": "Here is cloth",
            "Price": "100",
            "Category_ID": "1"
        },
        {
            "Product_Title": "Cloth",
            "Product_Description": "Here is cloth",
            "Price": "100",
            "Category_ID": "1"
        },
        {
            "Product_Title": "Cloth",
            "Product_Description": "Here is cloth",
            "Price": "100",
            "Category_ID": "1"
        }
    ]
}

我知道php具有内置的json_decode函数，但是在PHP文档中，它们仅显示如何处理数组.

I know php has a built in json_decode function, but in the PHP documentation they only show how to handle an array.

真的很感谢任何建议或帮助

Any advice or help is really appreciated

泰勒

推荐答案

如果您调用json_decode($data,true);，则数据将为:

If you call json_decode($data,true);, your data will be:

Array(
    "Product"=>Array(
        Array(
            "Product_Title"=>"Cloth",
            "Product_Description"=>"Here is cloth",
            "Price"=>"100",
            "Category_ID"=>"1"
        ),
        Array(
.............
        )
    )
);

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