json_decode PHP问题 [英] Problem with json_decode PHP

问题描述

我正在从python接收一个json数组，作为PHP中curl_exec的返回(第一个json PHP-> python，它返回另一个json)，并且由于语法错误而解码失败.接收到的json是有效的，但是以某种方式，如果我将此json转换为字符串并打印，则会得到一个包含29个字符的字符串，但是如果我打印strlen((string)$ my_json)，它会显示50.

I'm receiving a json array from python as the return of curl_exec in PHP (first json PHP -> python, that returns another json), and decode fails due to bad syntax. The json received is valid, but somehow if I cast this json to string and prints it I get a string with 29 characters, but if I print strlen((string)$my_json) it says 50.

代码如下:

$results = curl_exec($ch);
curl_close($ch);
var_dump(json_decode($results));

然后返回NULL.如果我执行以下操作

And that returns NULL. If I do the following

echo (string)$results;

它打印[[11，"stuffstuf"，"stuffs"]](29个字符)，它是一个有效的json.但是如果我这样做

It prints [[11, "stuffstuf", "stuffs"]] (29 chars), which is a valid json. But if I do

echo strlen((string)$results);

它打印50.

所以，我不知道发生了什么.任何想法将不胜感激=)

So, I don't know what is going on. Any thoughts would be appreciated =)

推荐答案

是否可能是您周围有一些html标记，在执行简单的echo时看不到?

Could it be that you have some html tags around it that you don't see when doing the simple echo?

尝试:echo htmlentities((string)$results);查看更多内容，或检查页面的html源.

Try: echo htmlentities((string)$results); to see more, or check the html source of the page.

如果json_decode()失败，则表明该字符串不是标准JSON.

If json_decode() fails, it means the string isn't standard JSON.

您还可以使用 json_last_error_msg()找出为什么它返回NULL的原因.如果json_decode中有任何错误，则会返回一条错误消息.

You can also use json_last_error_msg() to figure out why it returned NULL. That will return an error message if there was any error in json_decode.

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