PHP中的json_decode()问题 [英] json_decode() problems in PHP

问题描述

http://pastebin.com/Jp7WRPcz

以下JSON响应使用json_decode()

The following JSON response returns null using json_decode()

任何想法为何无效，以及如何使它有效解码.

Any ideas why it is invalid, and how can I make it valid to decode.

推荐答案

查看 http://jsonlint.com/

根据JSONLint，您遇到以下错误:

Accoring to JSONLint, you have the following error:

Parse error on line 82:
...            "text": "Make it easier for 
-----------------------^
Expecting 'STRING', 'NUMBER', 'NULL', 'TRUE', 'FALSE', '{', '['

错误在于字符串'\ x27s'

The error is with this in the string '\x27s'

第92行也一样.

"Roger\x27scompanion\x3cem\x3ehelped\x3c/em\x3ehimwiththeren"

用适当的unicode字符替换它们，或在斜杠转义字符串时添加一个额外的斜杠.

Replace them with their appropriate unicode characters or add an extra slash as one slash is escaping your string.

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